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5x^2-3x=180
We move all terms to the left:
5x^2-3x-(180)=0
a = 5; b = -3; c = -180;
Δ = b2-4ac
Δ = -32-4·5·(-180)
Δ = 3609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3609}=\sqrt{9*401}=\sqrt{9}*\sqrt{401}=3\sqrt{401}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{401}}{2*5}=\frac{3-3\sqrt{401}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{401}}{2*5}=\frac{3+3\sqrt{401}}{10} $
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